# -*- coding utf-8 -*-

"""

利用filter()筛选出回数

"""

def is_palindrome(n):

    s = str(n)

    if s == s[::-1]:            # s[::-1]为s的倒序

        return n

output = filter(is_palindrome, range(1, 1000))

print('1~1000:', list(output))

if list(filter(is_palindrome, range(1, 200))) == [1, 2, 3, 4, 5, 6, 7, 8, 9, 11, 22, 33, 44, 55, 66, 77, 88, 99, 101, 111, 121, 131, 141, 151, 161, 171, 181, 191]:

    print('success')

else:

    print('false')
